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M (2.71828) R^2 (1/y)^-1
(X^2)^1/2 (Force/Acceleration)
(X^2)^1/2 (Force/Acceleration)
Ok I'll explain, just to prove I did get it....Rick Lindsay said:M (2.71828) R^2 (1/y)^-1
(X^2)^1/2 (Force/Acceleration)
I'm not an engineer and don't even own a train!mwillems said:Actually it should have been
M (2.71828) R^2 (1/y)^-1
(X^2)^1/2 (Force/Acceleration) - S
...to get rid of the excess "S" at the end)
MW
PS I am an engineer by training and the originator of this post is very probably into engineering and/or physics as well!
then the tradesmen looks at it and says.. stupid engineers complicating the issues... why didn't the just say merry x-mass!?!?Rick Lindsay said:I am humbled by the folks who got or even worse, appreciated my holiday
wish. And yes, I am a physicist. I appreciate the correction, as well. The
addition of the ' -S ' at the end is the difference between physicists and
engineers. The physicist got the theory right while the engineer got the
right answer! :-]
Actually, you make a VERY good point and I'll try to stay off my soap-box.dent said:then the tradesmen looks at it and says.. stupid engineers complicating the issues... why didn't the just say merry x-mass!?!?![]()
If you're wondering i did enjoy it though, very cleaver
happy holidays all
take care
sam
didn't mean to make a deeper point, was just having some fun.. stay on your soap box, makes it a humours boardRick Lindsay said:Thanks again Sam, for posting a much deeper issue than my joking holiday wish.
Lindsay